[Development] QOptional

[Marc Mutz]

On Thursday 21 August 2014 16:52:05 Thiago Macieira wrote:
> But I'd like QOptional<QString> o = QString() result in a null
> (disengaged)  QOptional too.

Too clever for a general optional class, IMO:

  QOptional<QString> qs = QString();
  QOptional<std::string> ss = std::string();

qs will be disengaged and ss will be engaged. Hard to explain in the docs. 
Impossible to anticipate for new users of the class. Death row for template 
code.

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Marc Mutz <marc.mutz at kdab.com> | Senior Software Engineer
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