[Development] Should qMetaTypeId<const T>() == qMetaTypeId<T>() ?

[Jędrzej Nowacki]

On onsdag 24. august 2016 15.23.01 CEST Marc Mutz wrote:
> Hi,
> 
> Currently, it's not, which doesn't make much sense, does it?
> 
> So,
> 
>   template <typename T>
>   int qMetyTypeId<T>() {
>     return qMetaTypeIdHelper<typename std::remove_cv<T>::type>();
>   }
> 
> ?
> 
> (There's of course a lot more involved in this, registration should discard
> const, too, e.g.).
> 
> Thanks,
> Marc

Hi,

From C++ perspective const T and T are kind of separate types, metatype mimics 
that. QMetaType is used in many places and in some constness matters. 

Consider that example:
 QMetaType::typeName(qMetaTypeId<const QString>())
and
 QMetaType::typeName(qMetaTypeId<QString>())
The function is used in metaobject to compute signatures of invokables.

Cheers,
  Jędrek