[Interest] Access QVariant's raw data
Thiago Macieira
thiago.macieira at intel.com
Sun Apr 8 15:29:17 CEST 2012
On domingo, 8 de abril de 2012 13.00.28, Jonas Gehring wrote:
> Hi Thiago,
>
> On 4/8/12 5:16 AM, Thiago Macieira wrote:
> >> QVariant result = ...; // Just received from thread
> >> QMetaMethod method = ...; // Pass the result to this method
> >> method.invoke(receiver, QGenericArgument(result.typeName(),
> >>
> >> result.value<void *>()));
> >
> > You're not supposed to use QGenericArgument directly. Use Q_ARG.
>
> Thanks for your clarifications. Is there a way to achieve the desired
> behavior with Q_ARG? The main point is that I don't know the actual type
> of the result, but the QVariant does (although not via templates,
> apparently).
Then take a look at what Q_ARG does and replicate it for your code. It does
not involve value<void *>().
--
Thiago Macieira - thiago.macieira (AT) intel.com
Software Architect - Intel Open Source Technology Center
Intel Sweden AB - Registration Number: 556189-6027
Knarrarnäsgatan 15, 164 40 Kista, Stockholm, Sweden
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