[Interest] QMetaType::metaObjectForType

[Stephen Kelly]

On Monday, February 17, 2014 09:47:20 you wrote:
> Hi
> Thanks for your quick reply.
> This does indeed work, but I would be grateful if you could explain why
> 

> > Q_DECLARE_METATYPE(Widget)
> 
> Remove this line.

You don't pass around copies of QObject derived types because it is not 
copyable. You pass around pointers instead. So, you don't want 'Widget' to be 
a metatype, you want 'Widget*' to be a metatype so that you can put a Widget* 
in a QVariant for example.

You can use 

 Q_DECLARE_METATYPE(Widget*)

but it is not needed as of Qt 5.0. There's some background info here:

 http://steveire.wordpress.com/2011/03/16/implementing-qvariantqmetatype-features-with-template-tricks/

and the problems were solved and implemented in 5.0

 http://www.kdab.com/kdab-contributions-to-qt-5-0-part-1/

So, it's better to remove the Q_DECLARE_METATYPE that you don't need rather 
than add one that is wrong.

> > Class.cpp
> > const int WidgetTypeID = qRegisterMetaType<Widget>("Widget");
> 
> Register the pointer. Don't specify the string:
> 
>  qRegisterMetaType<Widget*>();

By using a string there, you run the risk of typos. The string is not needed 
and should not be used (even with Qt 4 code). 

Thanks,

-- 
Stephen Kelly <stephen.kelly at kdab.com> | Software Engineer
KDAB (Deutschland) GmbH & Co.KG, a KDAB Group Company
www.kdab.com || Germany +49-30-521325470 || Sweden (HQ) +46-563-540090
KDAB - Qt Experts - Platform-Independent Software Solutions
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