[Interest] Why there is no QChar::toLocal8Bit()?
Thiago Macieira
thiago.macieira at intel.com
Sat Apr 9 23:05:54 CEST 2016
On sábado, 9 de abril de 2016 19:45:52 PDT Prav wrote:
> Hi, Thiago Macieira.
>
> > It's intentional because it's superfluous. You can get the same by running
> >
> > QString(the_qchar).toLocal8Bit();
> >
> > converting to a multibyte 8-bit representation is a string operation
> > anyway.
> Multibyte?! I thought it should be like
>
> char QChar::toLocal8Bit() const;
>
> No?
No, as I said it's a multibyte operation.
--
Thiago Macieira - thiago.macieira (AT) intel.com
Software Architect - Intel Open Source Technology Center
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