[Qt-interest] New Bee Question: Quiting under following situation

[Nathan Carter]

Rahul,

A signal is not the only thing that can make a slot go off.  If you  
want to call a slot at a certain point in your code, simply call it as  
a function.  That is, you could replace the comment line in your code  
below with the following line.
	qApp->quit();

If you try this and it causes problems in your application because  
quitting at that point is too sudden (e.g., other things need to  
finish up first) then you could always have the quit take place a  
moment later, right before the event loop restarts, with the following  
line.
	QTimer::singleShot( 0, qApp, SLOT(quit()) );

Nathan


>
> From: qt-interest-bounces at trolltech.com [mailto:qt-interest-bounces at trolltech.com 
> ] On Behalf Of Rahulkumar Tibdewal
> Sent: Tuesday, June 09, 2009 8:18 AM
> To: qt-interest
> Subject: [Qt-interest] New Bee Question: Quiting under following  
> situation
>
> Hi All,
>
> I want to quit a application from the following code.
>
> QMessageBox::StandardButton reply;
> reply = QMessageBox::information(this, tr(“xyz”),tr(“xyz”));
> if(reply == QMessageBox::Ok)
> {
>                 //Some to be done here to close the application.
> }
>
> In the code above, I am having a problem in getting reference of  
> OKButton.
> So I was not able to quit application by using connect (okButton,  
> SIGNAL(clicked), qApp, SLOT(quit()));
>
> Please help me in getting rid of this situation.
>
> Thanks
> Rahul
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