[Qt-interest] Stumped by a simple dialog....

[Mike Inman]

Hi,

I have written a simple accessory program that loads a .ui form as a 
QDialog, has a bunch of buttons, does some simple stuff, then writes a file.

The basic execution order is:

QApplication app(argc, argv);
QDialog *diaog = loader.load( .ui file reference );
QMetaObject::connectSlotsByName(dialog);
dialog->show();
app.exec();

The dialog has several buttons that trigger QInputDialog::getText 
functions, and these behave as expected, the text is input and the form 
continues to execute.  It also has a button that generates the file and 
I use QMessageBox::information() to tells the user about a successful 
write, of if there's a reason the write wasn't done.

My problem is: when the QMessageBox::information() is exited, it causes 
the parent dialog (which is functioning as the only user interface for 
the app) to also exit - if I bypass the QMessageBox::information() 
calls, the app doesn't exit, but I also don't get my success/fail messages.

The exact call is:

QMessageBox::information(this, tr("Simple App Window Title"),

tr("success or fail message"),

QMessageBox::Ok,

QMessageBox::Ok);


Whether I parent the message box to the dialog (this) or the app (0), 
pressing the Ok causes the dialog (and thus the whole app) to exit.

Am I missing something obvious? 

Mike Inman