[Qt-interest] Constructing a QEnum with only a metatypeid.

[Thiago Macieira]

On Monday, 8 de August de 2011 20:43:06 MARTIN Pierre wrote:
> Hello,
> 
> Regarding my previous post, it may be too complicated after all. Below is a
> simplified version of the question…
> 
> Can someone provide me with an example of code showing how to construct a
> QVariant "v", based on a given QVariant::UserType "t" where "t" refers to a
> type registered for an enum type?  

QVariant v(t, 0);

The value will be default constructed. I hope you like your enums of value 0. 
The 0 above is not the value, it's a null pointer.

> Then when using qDebug() << v; i expect
> the type as well as the value to appear in stdout...

It will print the type name but not the value. Printing the value is not 
possible.

-- 
Thiago Macieira - thiago (AT) macieira.info - thiago (AT) kde.org
   Software Architect - Intel Open Source Technology Center
      PGP/GPG: 0x6EF45358; fingerprint:
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