[Qt-interest] unix SIGUSR1 signal on QT

[Brian McGillion]

> Den 10-02-2011 11:31, Brian McGillion skrev:
>> http://doc.qt.nokia.com/4.7-snapshot/unix-signals.html
>
> That doesn't really answer the question, but it's good to know.

Sorry but was the question not:

"""

Is it possible that I can receive the same signal
(kill(pidOf("main"),SIGUSR1); ) from a QT application so that any given
slot is called once the signal is received.

"""

That link shows how to catch a unix signal and convert it to a Qt signal
through QSocketNotifier. and that signal is connected to the slot
required.

Br,
Brian

> Gigin, the signals have nothing to do with Qt signals. You have to code
> it like you would in any other C or C++ project. Just be aware of the
> warning above: Don't call a Qt function or method while you are in the
> signal handler.
>
> Bo Thorsen.
>
>>> Hi,
>>> I am working on ARM based embedded target with linux 2.6.30.4. I am
>>> sending a signal from C code as mentioned :
>>>
>>> kill(pidOf("main"),SIGUSR1);
>>> The function pidOf returns the process ID of a process running on the
>>> unix
>>> machine. Whenever I execute my above code, it is sendinh signal to the
>>> "main" program and I am getting the printf signal mentioned in the
>>> signal
>>> handler of main program. The main.c is given below:void mysignal(int i
>>> ){printf("Signal is Called\n");
>>> }void main(){signal(SIGUSR1,mysignal);while(1) sleep(10);return;}
>>>
>>>
>>> Is it possible that I can receive the same signal
>>> (kill(pidOf("main"),SIGUSR1); ) from a QT application so that any given
>>> slot is called once the signal is received.
>
> Bo Thorsen,
> Fionia Software.
>
> --
>
> Expert Qt and C++ developer for hire
> Contact me if you need expert Qt help
> http://www.fioniasoftware.dk
>
> _______________________________________________
> Qt-interest mailing list
> Qt-interest at qt.nokia.com
> http://lists.qt.nokia.com/mailman/listinfo/qt-interest
>