[Interest] Who disconnects lambda expression slots?

[Nikos Chantziaras]

On 15/12/12 07:07, Thiago Macieira wrote:
> On sábado, 15 de dezembro de 2012 06.50.07, Nikos Chantziaras wrote:
>> On 15/12/12 06:33, Thiago Macieira wrote:
>>> I don't see your point. QObject::connect adds the connection object to a
>>> list. QObject::~QObject destroys the list.
>>
>> What I don't get is how QObject::connect() can tell where it was called
>> from.
>
> It can't.

That's what my question was actually about :)  Thanks for confirming.


>> How does it get to know that the 'foo' object is doing the
>> connection?  What if the connection is made from a non-member function?
>> [...]
>
> That's the point. It can't. This connection has absolutely no way of knowing
> when the receiver is deleted. It's entirely up to you to deal with it.
>
> There's an overload that accepts a receiver object and a functor as
> parameters.

I suppose it's undocumented at the moment then.  I was looking for it, 
since I imagined it would exist, but didn't find it in the docs which 
prompted me to post the question.