[Interest] Convert IPv6 to IPv4 ?

["Alexander Carôt"]

Hello Thiago, Hello Benjamin,

thanks for your replies !

In fact Thiago was precisely right with this:

> You probably mean you've got a v4-mapped IPv6 address, as
> ::ffff:192.0.2.1

As a quick hack I first converted this to a string and removed the first 7 characters but of course Thiagos solution is the way to do it. It works well - thanks a lot,

best regards

Alex


--
http://www.carot.de
Email : Alexander at Carot.de
Tel.: +49 (0)177 5719797


> Gesendet: Donnerstag, 21. April 2016 um 19:02 Uhr
> Von: "Thiago Macieira" <thiago.macieira at intel.com>
> An: interest at qt-project.org
> Betreff: Re: [Interest] Convert IPv6 to IPv4 ?
>
> On quinta-feira, 21 de abril de 2016 14:05:52 PDT Alexander Carôt wrote:
> > Hello,
> > 
> > I noticed that retrieving a sender's IP address of a QWebSocket via
> > ->peerAddress() returns an IPv6 socket address.
> > 
> > For certain reasons I need an IPv4 address so I wonder how it is possible to
> > either let ->peerAddress() return an IPv4 address or convert the IPv6
> > address to an IPv4 address.
> 
> Hello Alex
> 
> You probably mean you've got a v4-mapped IPv6 address, as
> 	::ffff:192.0.2.1
> 
> You should code as:
> 
> 	bool ok;
> 	quint32 ipv4 = hostaddr.toIPv4Address(&ok);
> 	if (ok) {
> 		// check my IPv4 ACL
> 	} else if (hostaddr.protocol() == QAbstractSocket::IPv6Protocol) {
> 		// check my IPv6 ACL
> 	} else {
> 		// uh... what?
> 	}
> 
> 
> -- 
> Thiago Macieira - thiago.macieira (AT) intel.com
>   Software Architect - Intel Open Source Technology Center
> 
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